3x^2=-60-27x

Solution for 3x^2=-60-27x equation:

3x^2=-60-27x

We move all terms to the left:

3x^2-(-60-27x)=0

We add all the numbers together, and all the variables

3x^2-(-27x-60)=0

We get rid of parentheses

3x^2+27x+60=0

a = 3; b = 27; c = +60;
Δ = b2-4ac
Δ = 272-4·3·60
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-3}{2*3}=\frac{-30}{6}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+3}{2*3}=\frac{-24}{6}
=-4
$